终极大师 (UMA) #73
2018-12-07 | 普通 |


Stitcher's Apprentice (拼接师的学徒)
Stitcher's Apprentice
{1}{U}
Creature — Homunculus
Creature — Homunculus
生物~造妖
{1}{U}, {T}: Create a 2/2 blue Homunculus creature token, then sacrifice a creature.
{1}{U}, {T}: Create a 2/2 blue Homunculus creature token, then sacrifice a creature.
{1}{U},{T}:派出一个2/2蓝色造妖衍生生物,然后牺牲一个生物。
"Oglor create life, Oglor take it away. Oglor god! ... until Master return."
"Oglor create life, Oglor take it away. Oglor god! ... until Master return."
"Oglor create life, Oglor take it away. Oglor god! ... until Master return."
🖌 Johann Bodin
1/2
标准
炼金
先驱
探险
摩登
史迹
薪传
争锋
特选
不朽
指挥官
纯铁
翻译信息
牌名翻译:官方中文
规则叙述翻译:Forge Data
背景叙述翻译:N/A
牌图来源:N/A
规则叙述翻译:Forge Data
背景叙述翻译:N/A
牌图来源:N/A
单卡释疑
-
(2018-12-07 gpt)
任何会在造妖衍生物进战场时触发的异能,都会在你牺牲生物之后结算。
Any abilities that trigger on the Homunculus token entering the battlefield will resolve after you’ve sacrificed a creature. -
(2018-12-07 gpt)
你为拼接师的异能牺牲的生物,可以是你刚派出的人造妖,也可以是拼接师的本身。
The creature you sacrifice for the ability of Stitcher’s Apprentice could be the Homunculus you’ve just created. It could also be Stitcher’s Apprentice itself. -
(2018-12-07 gpt)
你是在起动式异能结算的过程中派出衍生物并牺牲生物。在这两个动作之间无法发生任何事情,且没有牌手能采取任何动作。
You create a token and sacrifice a creature all while the activated ability is resolving. Nothing can happen between the two, and no player may choose to take actions.