单卡释疑

• (2020-11-10 official)

  如果某生物的力量因故小于0，则在计算力量总和时会将其当作负数计算（其他生物的力量加总后减去此数值）。这样就能让力量总和等于或大于5的生物活下来。

  If a creature's power is somehow less than 0, it subtracts from the total power of the other creatures its controller chooses. This can cause creatures with power 5 or greater to survive.

• (2020-11-10 official)

  于斩杀猛兽结算时，首先由轮到该回合的牌手选择救下哪些生物，然后其他牌手按照回合顺序依次作出选择，牌手在作选择时已知道之前牌手的选择为何。然后同时牺牲所有未被选择的生物。

  As Slaughter the Strong resolves, first the player whose turn it is chooses which creatures will be spared, then each other player in turn order does the same knowing the choices made before them. Then all the creatures not chosen are sacrificed simultaneously.

• (2020-11-10 official)

  斩杀猛兽会让每位牌手各选择任意数量的生物，然后检查各牌手以此法选择的生物之力量总和是否等于或小于4。举例来说，你能救下两个2/2生物，或一个1/1生物和一个3/3生物，但不能全部救下这四个生物。

  Slaughter the Strong has each player choose any number of creatures and then checks that the total power of creatures each player chose this way is 4 or less. For example, you could save two 2/2 creatures, or a 1/1 and a 3/3 creature, but not all four of those creatures.